Home
Search
 
What's New
Index
Books
Links
Q & A
Newsletter
Banners
 
Feedback
Tip Jar
 
C# Helper...
 
XML RSS Feed
Follow VBHelper on Twitter
 
 
 
MSDN Visual Basic Community
 
 
 
 
 
TitleDraw a butterfly curve
DescriptionThis example shows how to draw a butterfly curve in Visual Basic 6.
Keywordsgraphics, curve, butterfly, butterfly curve
CategoriesGraphics
 
This program uses the following equations to draw the butterfly curve:

    x = Cos(t) * Exp(Cos(t)) - 2 * Cos(4 * t) - Sin(t / 12) ^ 5
    y = Sin(t) * Exp(Cos(t)) - 2 * Cos(4 * t) - Sin(t / 12) ^ 5

Subroutine DrawCurve loops variable t through the values 0 to 24 * Pi to generate and connect the curve's points.

 
Private Sub DrawCurve()
Const PI As Double = 3.14159265
Const NUM_LINES As Long = 5000
Const NUM_COLORS As Integer = 6
Dim i As Long
Dim t As Double
Dim expr As Double
Dim x As Double
Dim y As Double
Dim colors(0 To NUM_COLORS - 1) As OLE_COLOR

    ' Initialize colors.
    i = 0
    colors(i) = RGB(255, 0, 0): i = i + 1
    colors(i) = RGB(0, 255, 0): i = i + 1
    colors(i) = RGB(0, 0, 255): i = i + 1
    colors(i) = RGB(255, 255, 0): i = i + 1
    colors(i) = RGB(0, 255, 255): i = i + 1
    colors(i) = RGB(255, 0, 255): i = i + 1

    ' Get the first point.
    t = 0
    expr = Exp(Cos(t)) - 2 * Cos(4 * t) - Sin(t / 12) ^ 5
    x = Cos(t) * expr
    y = Sin(t) * expr
    ' I switch these for vertical symmetry.
    Me.CurrentX = y
    Me.CurrentY = -x
    Me.DrawWidth = 2

    For i = 1 To NUM_LINES - 1
        t = i * 24# * PI / NUM_LINES
        expr = Exp(Cos(t)) - 2 * Cos(4 * t) - Sin(t / 12) ^ _
            5
        x = Cos(t) * expr
        y = Sin(t) * expr

        'Line -(y, -x),vbblue
        Line -(y, -x), colors((i * 24 / NUM_LINES) Mod _
            NUM_COLORS)
    Next i
End Sub
 
For more information on graphics programming in Visual Basic 6, see my book Ready-to-Run Visual Basic Graphics Programming.
 
 
Copyright © 1997-2010 Rocky Mountain Computer Consulting, Inc.   All rights reserved.
  Updated